This is an inefficient python implementation of the problem.
def add(A,B):
n = len(A)
C = [0 for x in range(n+1)]
carry = 0
A.insert(0,0)
B.insert(0,0)
for i in range(n,-1,-1):
z = A[i] + B[i] + carry
if z == 0:
C[i] = 0
elif z == 1:
C[i] = 1
elif z == 2:
C[i] = 0
carry = 1
elif z == 3:
C[i] = 1
carry = 1
else:
raise "Something went wrong"
return C
add([1,1,1],[1,1,1])
No comments:
Post a Comment